Theorem simplrd

Description: Deduction eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019)

	Ref	Expression
Hypothesis	simplrd.1	|- ( ph -> ( ( ps /\ ch ) /\ th ) )
Assertion	simplrd	|- ( ph -> ch )

Proof

Step	Hyp	Ref	Expression
1		simplrd.1	|- ( ph -> ( ( ps /\ ch ) /\ th ) )
2	1	simpld	|- ( ph -> ( ps /\ ch ) )
3	2	simprd	|- ( ph -> ch )