Metamath Proof Explorer


Theorem sseq0b

Description: The only subclass of the empty class is itself. (Contributed by NM, 7-Mar-2007) (Proof shortened by Andrew Salmon, 26-Jun-2011) Strengthen sseq0 to a biconditional. (Revised by BJ, 19-Jul-2026)

Ref Expression
Assertion sseq0b
|- ( A = (/) -> ( B C_ A <-> B = (/) ) )

Proof

Step Hyp Ref Expression
1 sseq2
 |-  ( A = (/) -> ( B C_ A <-> B C_ (/) ) )
2 ss0b
 |-  ( B C_ (/) <-> B = (/) )
3 1 2 bitrdi
 |-  ( A = (/) -> ( B C_ A <-> B = (/) ) )