Metamath Proof Explorer


Theorem sseq0b

Description: The only subclass of the empty class is itself. (Contributed by NM, 7-Mar-2007) Strengthen sseq0 to a biconditional. (Revised by BJ, 19-Jul-2026)

Ref Expression
Assertion sseq0b ( 𝐴 = ∅ → ( 𝐵 ⊆ 𝐴 ↔ 𝐵 = ∅ ) )

Proof

Step Hyp Ref Expression
1 sseq2 ⊢ ( 𝐴 = ∅ → ( 𝐵 ⊆ 𝐴 ↔ 𝐵 ⊆ ∅ ) )
2 ss0b ⊢ ( 𝐵 ⊆ ∅ ↔ 𝐵 = ∅ )
3 1 2 bitrdi ⊢ ( 𝐴 = ∅ → ( 𝐵 ⊆ 𝐴 ↔ 𝐵 = ∅ ) )