Metamath Proof Explorer


Theorem uneq2d

Description: Deduction adding union to the left in a class equality. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypothesis uneq1d.1
|- ( ph -> A = B )
Assertion uneq2d
|- ( ph -> ( C u. A ) = ( C u. B ) )

Proof

Step Hyp Ref Expression
1 uneq1d.1
 |-  ( ph -> A = B )
2 uneq2
 |-  ( A = B -> ( C u. A ) = ( C u. B ) )
3 1 2 syl
 |-  ( ph -> ( C u. A ) = ( C u. B ) )