Metamath Proof Explorer


Theorem 0mod

Description: Special case: 0 modulo a positive real number is 0. (Contributed by Mario Carneiro, 22-Feb-2014)

Ref Expression
Assertion 0mod ⊢ N ∈ ℝ + → 0 mod N = 0

Proof

Step Hyp Ref Expression
1 0re ⊢ 0 ∈ ℝ
2 1 jctl ⊢ N ∈ ℝ + → 0 ∈ ℝ ∧ N ∈ ℝ +
3 rpgt0 ⊢ N ∈ ℝ + → 0 < N
4 0le0 ⊢ 0 ≤ 0
5 3 4 jctil ⊢ N ∈ ℝ + → 0 ≤ 0 ∧ 0 < N
6 modid ⊢ 0 ∈ ℝ ∧ N ∈ ℝ + ∧ 0 ≤ 0 ∧ 0 < N → 0 mod N = 0
7 2 5 6 syl2anc ⊢ N ∈ ℝ + → 0 mod N = 0