Metamath Proof Explorer


Theorem 0nelfb

Description: No filter base contains the empty set. (Contributed by Jeff Hankins, 1-Sep-2009) (Revised by Mario Carneiro, 28-Jul-2015)

Ref Expression
Assertion 0nelfb ⊢ F ∈ fBas ⁡ B → ¬ ∅ ∈ F

Proof

Step Hyp Ref Expression
1 elfvdm ⊢ F ∈ fBas ⁡ B → B ∈ dom ⁡ fBas
2 isfbas ⊢ B ∈ dom ⁡ fBas → F ∈ fBas ⁡ B ↔ F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
3 1 2 syl ⊢ F ∈ fBas ⁡ B → F ∈ fBas ⁡ B ↔ F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
4 3 ibi ⊢ F ∈ fBas ⁡ B → F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
5 simpr2 ⊢ F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅ → ∅ ∉ F
6 4 5 syl ⊢ F ∈ fBas ⁡ B → ∅ ∉ F
7 df-nel ⊢ ∅ ∉ F ↔ ¬ ∅ ∈ F
8 6 7 sylib ⊢ F ∈ fBas ⁡ B → ¬ ∅ ∈ F