Metamath Proof Explorer


Theorem fbsspw

Description: A filter base on a set is a subset of the power set. (Contributed by Stefan O'Rear, 28-Jul-2015)

Ref Expression
Assertion fbsspw ⊢ F ∈ fBas ⁡ B → F ⊆ 𝒫 B

Proof

Step Hyp Ref Expression
1 elfvdm ⊢ F ∈ fBas ⁡ B → B ∈ dom ⁡ fBas
2 isfbas ⊢ B ∈ dom ⁡ fBas → F ∈ fBas ⁡ B ↔ F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
3 1 2 syl ⊢ F ∈ fBas ⁡ B → F ∈ fBas ⁡ B ↔ F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
4 3 ibi ⊢ F ∈ fBas ⁡ B → F ⊆ 𝒫 B ∧ F ≠ ∅ ∧ ∅ ∉ F ∧ ∀ x ∈ F ∀ y ∈ F F ∩ 𝒫 x ∩ y ≠ ∅
5 4 simpld ⊢ F ∈ fBas ⁡ B → F ⊆ 𝒫 B