Metamath Proof Explorer


Theorem 1sdom2

Description: Ordinal 1 is strictly dominated by ordinal 2. For a shorter proof requiring ax-un , see 1sdom2ALT . (Contributed by NM, 4-Apr-2007) Avoid ax-un . (Revised by BTernaryTau, 8-Dec-2024)

Ref Expression
Assertion 1sdom2 ⊢ 1 𝑜 ≺ 2 𝑜

Proof

Step Hyp Ref Expression
1 2on0 ⊢ 2 𝑜 ≠ ∅
2 2oex ⊢ 2 𝑜 ∈ V
3 2 0sdom ⊢ ∅ ≺ 2 𝑜 ↔ 2 𝑜 ≠ ∅
4 1 3 mpbir ⊢ ∅ ≺ 2 𝑜
5 0sdom1dom ⊢ ∅ ≺ 2 𝑜 ↔ 1 𝑜 ≼ 2 𝑜
6 4 5 mpbi ⊢ 1 𝑜 ≼ 2 𝑜
7 snnen2o ⊢ ¬ ∅ ≈ 2 𝑜
8 df1o2 ⊢ 1 𝑜 = ∅
9 8 breq1i ⊢ 1 𝑜 ≈ 2 𝑜 ↔ ∅ ≈ 2 𝑜
10 7 9 mtbir ⊢ ¬ 1 𝑜 ≈ 2 𝑜
11 brsdom ⊢ 1 𝑜 ≺ 2 𝑜 ↔ 1 𝑜 ≼ 2 𝑜 ∧ ¬ 1 𝑜 ≈ 2 𝑜
12 6 10 11 mpbir2an ⊢ 1 𝑜 ≺ 2 𝑜