Metamath Proof Explorer


Theorem 3eqtr4d

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-1995) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses 3eqtr4d.1 φ A = B
3eqtr4d.2 φ C = A
3eqtr4d.3 φ D = B
Assertion 3eqtr4d φ C = D

Proof

Step Hyp Ref Expression
1 3eqtr4d.1 φ A = B
2 3eqtr4d.2 φ C = A
3 3eqtr4d.3 φ D = B
4 3 1 eqtr4d φ D = A
5 2 4 eqtr4d φ C = D