Metamath Proof Explorer


Theorem 3netr4d

Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 24-Jul-2012) (Proof shortened by Wolf Lammen, 21-Nov-2019)

Ref Expression
Hypotheses 3netr4d.1 ⊢ φ → A ≠ B
3netr4d.2 ⊢ φ → C = A
3netr4d.3 ⊢ φ → D = B
Assertion 3netr4d ⊢ φ → C ≠ D

Proof

Step Hyp Ref Expression
1 3netr4d.1 ⊢ φ → A ≠ B
2 3netr4d.2 ⊢ φ → C = A
3 3netr4d.3 ⊢ φ → D = B
4 2 1 eqnetrd ⊢ φ → C ≠ B
5 4 3 neeqtrrd ⊢ φ → C ≠ D