Metamath Proof Explorer


Theorem 3olt9o

Description: Ordinal 3 is less than ordinal 9. (Contributed by BTernaryTau, 17-Oct-2026)

Ref Expression
Assertion 3olt9o Could not format assertion : No typesetting found for |- 3o e. 9o with typecode |-

Proof

Step Hyp Ref Expression
1 3on ⊢ 3 𝑜 ∈ On
2 sucidg ⊢ 3 𝑜 ∈ On → 3 𝑜 ∈ suc ⁡ 3 𝑜
3 1 2 ax-mp ⊢ 3 𝑜 ∈ suc ⁡ 3 𝑜
4 df-4o ⊢ 4 𝑜 = suc ⁡ 3 𝑜
5 3 4 eleqtrri ⊢ 3 𝑜 ∈ 4 𝑜
6 4olt9o Could not format 4o e. 9o : No typesetting found for |- 4o e. 9o with typecode |-
7 9on Could not format 9o e. On : No typesetting found for |- 9o e. On with typecode |-
8 ontr1 Could not format ( 9o e. On -> ( ( 3o e. 4o /\ 4o e. 9o ) -> 3o e. 9o ) ) : No typesetting found for |- ( 9o e. On -> ( ( 3o e. 4o /\ 4o e. 9o ) -> 3o e. 9o ) ) with typecode |-
9 7 8 ax-mp Could not format ( ( 3o e. 4o /\ 4o e. 9o ) -> 3o e. 9o ) : No typesetting found for |- ( ( 3o e. 4o /\ 4o e. 9o ) -> 3o e. 9o ) with typecode |-
10 5 6 9 mp2an Could not format 3o e. 9o : No typesetting found for |- 3o e. 9o with typecode |-