Metamath Proof Explorer


Theorem 4olt9o

Description: Ordinal 4 is less than ordinal 9. (Contributed by BTernaryTau, 17-Oct-2026)

Ref Expression
Assertion 4olt9o Could not format assertion : No typesetting found for |- 4o e. 9o with typecode |-

Proof

Step Hyp Ref Expression
1 4on ⊢ 4 𝑜 ∈ On
2 sucidg ⊢ 4 𝑜 ∈ On → 4 𝑜 ∈ suc ⁡ 4 𝑜
3 1 2 ax-mp ⊢ 4 𝑜 ∈ suc ⁡ 4 𝑜
4 df-5o Could not format 5o = suc 4o : No typesetting found for |- 5o = suc 4o with typecode |-
5 3 4 eleqtrri Could not format 4o e. 5o : No typesetting found for |- 4o e. 5o with typecode |-
6 5olt9o Could not format 5o e. 9o : No typesetting found for |- 5o e. 9o with typecode |-
7 9on Could not format 9o e. On : No typesetting found for |- 9o e. On with typecode |-
8 ontr1 Could not format ( 9o e. On -> ( ( 4o e. 5o /\ 5o e. 9o ) -> 4o e. 9o ) ) : No typesetting found for |- ( 9o e. On -> ( ( 4o e. 5o /\ 5o e. 9o ) -> 4o e. 9o ) ) with typecode |-
9 7 8 ax-mp Could not format ( ( 4o e. 5o /\ 5o e. 9o ) -> 4o e. 9o ) : No typesetting found for |- ( ( 4o e. 5o /\ 5o e. 9o ) -> 4o e. 9o ) with typecode |-
10 5 6 9 mp2an Could not format 4o e. 9o : No typesetting found for |- 4o e. 9o with typecode |-