Metamath Proof Explorer


Theorem 3orbi123d

Description: Deduction joining 3 equivalences to form equivalence of disjunctions. (Contributed by NM, 20-Apr-1994)

Ref Expression
Hypotheses bi3d.1 ⊢ φ → ψ ↔ χ
bi3d.2 ⊢ φ → θ ↔ τ
bi3d.3 ⊢ φ → η ↔ ζ
Assertion 3orbi123d ⊢ φ → ψ ∨ θ ∨ η ↔ χ ∨ τ ∨ ζ

Proof

Step Hyp Ref Expression
1 bi3d.1 ⊢ φ → ψ ↔ χ
2 bi3d.2 ⊢ φ → θ ↔ τ
3 bi3d.3 ⊢ φ → η ↔ ζ
4 1 2 orbi12d ⊢ φ → ψ ∨ θ ↔ χ ∨ τ
5 4 3 orbi12d ⊢ φ → ψ ∨ θ ∨ η ↔ χ ∨ τ ∨ ζ
6 df-3or ⊢ ψ ∨ θ ∨ η ↔ ψ ∨ θ ∨ η
7 df-3or ⊢ χ ∨ τ ∨ ζ ↔ χ ∨ τ ∨ ζ
8 5 6 7 3bitr4g ⊢ φ → ψ ∨ θ ∨ η ↔ χ ∨ τ ∨ ζ