Metamath Proof Explorer


Theorem abeqinbi

Description: Intersection with class abstraction and equivalent wff's. (Contributed by Peter Mazsa, 21-Jul-2021)

Ref Expression
Hypotheses abeqinbi.1 A = B C
abeqinbi.2 B = x | φ
abeqinbi.3 x C φ ψ
Assertion abeqinbi A = x C | ψ

Proof

Step Hyp Ref Expression
1 abeqinbi.1 A = B C
2 abeqinbi.2 B = x | φ
3 abeqinbi.3 x C φ ψ
4 1 2 abeqin A = x C | φ
5 4 3 rabimbieq A = x C | ψ