Metamath Proof Explorer


Theorem abssi

Description: Inference of abstraction subclass from implication. (Contributed by NM, 20-Jan-2006)

Ref Expression
Hypothesis abssi.1 ⊢ φ → x ∈ A
Assertion abssi ⊢ x | φ ⊆ A

Proof

Step Hyp Ref Expression
1 abssi.1 ⊢ φ → x ∈ A
2 1 ss2abi ⊢ x | φ ⊆ x | x ∈ A
3 abid2 ⊢ x | x ∈ A = A
4 2 3 sseqtri ⊢ x | φ ⊆ A