Metamath Proof Explorer


Theorem addeq0

Description: Two complex numbers add up to zero iff they are each other's opposites. (Contributed by Thierry Arnoux, 2-May-2017)

Ref Expression
Assertion addeq0 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B = 0 ↔ A = − B

Proof

Step Hyp Ref Expression
1 0cnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 0 ∈ ℂ
2 simpr ⊢ A ∈ ℂ ∧ B ∈ ℂ → B ∈ ℂ
3 simpl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ∈ ℂ
4 1 2 3 subadd2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 0 − B = A ↔ A + B = 0
5 df-neg ⊢ − B = 0 − B
6 5 eqeq1i ⊢ − B = A ↔ 0 − B = A
7 eqcom ⊢ − B = A ↔ A = − B
8 6 7 bitr3i ⊢ 0 − B = A ↔ A = − B
9 4 8 bitr3di ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B = 0 ↔ A = − B