Metamath Proof Explorer


Theorem afv0fv0

Description: If the value of the alternative function at an argument is the empty set, the function's value at this argument is the empty set. (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion afv0fv0 ⊢ F ''' A = ∅ → F ⁡ A = ∅

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 eleq1a ⊢ ∅ ∈ V → F ''' A = ∅ → F ''' A ∈ V
3 1 2 ax-mp ⊢ F ''' A = ∅ → F ''' A ∈ V
4 afvvfveq ⊢ F ''' A ∈ V → F ''' A = F ⁡ A
5 eqeq1 ⊢ F ''' A = F ⁡ A → F ''' A = ∅ ↔ F ⁡ A = ∅
6 5 biimpd ⊢ F ''' A = F ⁡ A → F ''' A = ∅ → F ⁡ A = ∅
7 4 6 syl ⊢ F ''' A ∈ V → F ''' A = ∅ → F ⁡ A = ∅
8 3 7 mpcom ⊢ F ''' A = ∅ → F ⁡ A = ∅