Metamath Proof Explorer


Theorem afvvfveq

Description: The value of the alternative function at a set as argument equals the function's value at this argument. (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion afvvfveq ⊢ F ''' A ∈ B → F ''' A = F ⁡ A

Proof

Step Hyp Ref Expression
1 nvelim ⊢ F ''' A = V → ¬ F ''' A ∈ B
2 1 necon2ai ⊢ F ''' A ∈ B → F ''' A ≠ V
3 afvnufveq ⊢ F ''' A ≠ V → F ''' A = F ⁡ A
4 2 3 syl ⊢ F ''' A ∈ B → F ''' A = F ⁡ A