Metamath Proof Explorer


Theorem afvnufveq

Description: The value of the alternative function at a set as argument equals the function's value at this argument. (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion afvnufveq ⊢ F ''' A ≠ V → F ''' A = F ⁡ A

Proof

Step Hyp Ref Expression
1 afvfundmfveq ⊢ F defAt A → F ''' A = F ⁡ A
2 afvnfundmuv ⊢ ¬ F defAt A → F ''' A = V
3 1 2 nsyl5 ⊢ ¬ F ''' A = F ⁡ A → F ''' A = V
4 3 necon1ai ⊢ F ''' A ≠ V → F ''' A = F ⁡ A