Metamath Proof Explorer


Theorem afv0fv0

Description: If the value of the alternative function at an argument is the empty set, the function's value at this argument is the empty set. (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion afv0fv0 ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ‘ 𝐴 ) = ∅ )

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 eleq1a ⊢ ( ∅ ∈ V → ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ''' 𝐴 ) ∈ V ) )
3 1 2 ax-mp ⊢ ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ''' 𝐴 ) ∈ V )
4 afvvfveq ⊢ ( ( 𝐹 ''' 𝐴 ) ∈ V → ( 𝐹 ''' 𝐴 ) = ( 𝐹 ‘ 𝐴 ) )
5 eqeq1 ⊢ ( ( 𝐹 ''' 𝐴 ) = ( 𝐹 ‘ 𝐴 ) → ( ( 𝐹 ''' 𝐴 ) = ∅ ↔ ( 𝐹 ‘ 𝐴 ) = ∅ ) )
6 5 biimpd ⊢ ( ( 𝐹 ''' 𝐴 ) = ( 𝐹 ‘ 𝐴 ) → ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ‘ 𝐴 ) = ∅ ) )
7 4 6 syl ⊢ ( ( 𝐹 ''' 𝐴 ) ∈ V → ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ‘ 𝐴 ) = ∅ ) )
8 3 7 mpcom ⊢ ( ( 𝐹 ''' 𝐴 ) = ∅ → ( 𝐹 ‘ 𝐴 ) = ∅ )