Metamath Proof Explorer


Theorem afvvv

Description: If a function's value at an argument is a set, the argument is also a set. (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion afvvv ⊢ F ''' A ∈ B → A ∈ V

Proof

Step Hyp Ref Expression
1 afvprc ⊢ ¬ A ∈ V → F ''' A = V
2 nvelim ⊢ F ''' A = V → ¬ F ''' A ∈ B
3 1 2 syl ⊢ ¬ A ∈ V → ¬ F ''' A ∈ B
4 3 con4i ⊢ F ''' A ∈ B → A ∈ V