Metamath Proof Explorer


Theorem ancomsd

Description: Deduction commuting conjunction in antecedent. (Contributed by NM, 12-Dec-2004)

Ref Expression
Hypothesis ancomsd.1 ⊢ φ → ψ ∧ χ → θ
Assertion ancomsd ⊢ φ → χ ∧ ψ → θ

Proof

Step Hyp Ref Expression
1 ancomsd.1 ⊢ φ → ψ ∧ χ → θ
2 1 expcomd ⊢ φ → χ → ψ → θ
3 2 impd ⊢ φ → χ ∧ ψ → θ