Metamath Proof Explorer


Axiom ax-hvmul0

Description: Scalar multiplication by zero. We can derive the existence of the negative of a vector from this axiom (see hvsubid and hvsubval ). (Contributed by NM, 29-May-1999) (New usage is discouraged.)

Ref Expression
Assertion ax-hvmul0 ⊢ A ∈ ℋ → 0 ⋅ ℎ A = 0 ℎ

Detailed syntax breakdown

Step Hyp Ref Expression
0 cA class A
1 chba class ℋ
2 0 1 wcel wff A ∈ ℋ
3 cc0 class 0
4 csm class ⋅ ℎ
5 3 0 4 co class 0 ⋅ ℎ A
6 c0v class 0 ℎ
7 5 6 wceq wff 0 ⋅ ℎ A = 0 ℎ
8 2 7 wi wff A ∈ ℋ → 0 ⋅ ℎ A = 0 ℎ