Metamath Proof Explorer


Theorem bicomd

Description: Commute two sides of a biconditional in a deduction. (Contributed by NM, 14-May-1993)

Ref Expression
Hypothesis bicomd.1 φ ψ χ
Assertion bicomd φ χ ψ

Proof

Step Hyp Ref Expression
1 bicomd.1 φ ψ χ
2 bicom ψ χ χ ψ
3 1 2 sylib φ χ ψ