Metamath Proof Explorer


Theorem bicomd

Description: Commute two sides of a biconditional in a deduction. (Contributed by NM, 14-May-1993)

Ref Expression
Hypothesis bicomd.1 φψχ
Assertion bicomd φχψ

Proof

Step Hyp Ref Expression
1 bicomd.1 φψχ
2 bicom ψχχψ
3 1 2 sylib φχψ