Metamath Proof Explorer


Theorem bicomd

Description: Commute two sides of a biconditional in a deduction. (Contributed by NM, 14-May-1993)

Ref Expression
Hypothesis bicomd.1 ⊢ φ → ψ ↔ χ
Assertion bicomd ⊢ φ → χ ↔ ψ

Proof

Step Hyp Ref Expression
1 bicomd.1 ⊢ φ → ψ ↔ χ
2 bicom ⊢ ψ ↔ χ ↔ χ ↔ ψ
3 1 2 sylib ⊢ φ → χ ↔ ψ