Metamath Proof Explorer


Theorem bj-cbv2v

Description: Version of cbv2 with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 16-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Hypotheses bj-cbv2v.1 ⊢ Ⅎ x φ
bj-cbv2v.2 ⊢ Ⅎ y φ
bj-cbv2v.3 ⊢ φ → Ⅎ y ψ
bj-cbv2v.4 ⊢ φ → Ⅎ x χ
bj-cbv2v.5 ⊢ φ → x = y → ψ ↔ χ
Assertion bj-cbv2v ⊢ φ → ∀ x ψ ↔ ∀ y χ

Proof

Step Hyp Ref Expression
1 bj-cbv2v.1 ⊢ Ⅎ x φ
2 bj-cbv2v.2 ⊢ Ⅎ y φ
3 bj-cbv2v.3 ⊢ φ → Ⅎ y ψ
4 bj-cbv2v.4 ⊢ φ → Ⅎ x χ
5 bj-cbv2v.5 ⊢ φ → x = y → ψ ↔ χ
6 2 nf5ri ⊢ φ → ∀ y φ
7 1 nfal ⊢ Ⅎ x ∀ y φ
8 7 nf5ri ⊢ ∀ y φ → ∀ x ∀ y φ
9 6 8 syl ⊢ φ → ∀ x ∀ y φ
10 3 nf5rd ⊢ φ → ψ → ∀ y ψ
11 4 nf5rd ⊢ φ → χ → ∀ x χ
12 10 11 5 bj-cbv2hv ⊢ ∀ x ∀ y φ → ∀ x ψ ↔ ∀ y χ
13 9 12 syl ⊢ φ → ∀ x ψ ↔ ∀ y χ