Metamath Proof Explorer


Theorem bj-fvsnun1

Description: The value of a function with one of its ordered pairs replaced, at arguments other than the replaced one. (Contributed by NM, 23-Sep-2007) Put in deduction form and remove two sethood hypotheses. (Revised by BJ, 18-Mar-2023)

Ref Expression
Hypotheses bj-fvsnun.un ⊢ φ → G = F ↾ C ∖ A ∪ A B
bj-fvsnun1.eldif ⊢ φ → D ∈ C ∖ A
Assertion bj-fvsnun1 ⊢ φ → G ⁡ D = F ⁡ D

Proof

Step Hyp Ref Expression
1 bj-fvsnun.un ⊢ φ → G = F ↾ C ∖ A ∪ A B
2 bj-fvsnun1.eldif ⊢ φ → D ∈ C ∖ A
3 eldifsnneq ⊢ D ∈ C ∖ A → ¬ D = A
4 2 3 syl ⊢ φ → ¬ D = A
5 1 4 bj-fununsn1 ⊢ φ → G ⁡ D = F ↾ C ∖ A ⁡ D
6 2 fvresd ⊢ φ → F ↾ C ∖ A ⁡ D = F ⁡ D
7 5 6 eqtrd ⊢ φ → G ⁡ D = F ⁡ D