Metamath Proof Explorer


Theorem bj-opabssvv

Description: A variant of relopabiv (which could be proved from it, similarly to relxp from xpss ). (Contributed by BJ, 28-Dec-2023)

Ref Expression
Assertion bj-opabssvv ⊢ x y | φ ⊆ V × V

Proof

Step Hyp Ref Expression
1 vex ⊢ x ∈ V
2 vex ⊢ y ∈ V
3 1 2 pm3.2i ⊢ x ∈ V ∧ y ∈ V
4 3 a1i ⊢ φ → x ∈ V ∧ y ∈ V
5 4 ssopab2i ⊢ x y | φ ⊆ x y | x ∈ V ∧ y ∈ V
6 df-xp ⊢ V × V = x y | x ∈ V ∧ y ∈ V
7 5 6 sseqtrri ⊢ x y | φ ⊆ V × V