Metamath Proof Explorer


Theorem bj-ssblem2

Description: An instance of ax-11 proved without it. The converse may not be provable without ax-11 (since using alcomimw would require a DV on ph , x , which defeats the purpose). (Contributed by BJ, 22-Dec-2020) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ssblem2 ⊢ ∀ x ∀ y y = t → x = y → φ → ∀ y ∀ x y = t → x = y → φ

Proof

Step Hyp Ref Expression
1 equequ1 ⊢ y = z → y = t ↔ z = t
2 equequ2 ⊢ y = z → x = y ↔ x = z
3 2 imbi1d ⊢ y = z → x = y → φ ↔ x = z → φ
4 1 3 imbi12d ⊢ y = z → y = t → x = y → φ ↔ z = t → x = z → φ
5 4 alcomimw ⊢ ∀ x ∀ y y = t → x = y → φ → ∀ y ∀ x y = t → x = y → φ