Metamath Proof Explorer


Theorem bj-vtoclg1f

Description: Reprove vtoclg1f from bj-vtoclg1f1 . This removes dependency on ax-ext , df-cleq and df-v . Use bj-vtoclg1fv instead when sufficient (in particular when V is substituted for _V ). (Contributed by BJ, 14-Sep-2019) (Proof modification is discouraged.)

Ref Expression
Hypotheses bj-vtoclg1f.nf ⊢ Ⅎ x ψ
bj-vtoclg1f.maj ⊢ x = A → φ → ψ
bj-vtoclg1f.min ⊢ φ
Assertion bj-vtoclg1f ⊢ A ∈ V → ψ

Proof

Step Hyp Ref Expression
1 bj-vtoclg1f.nf ⊢ Ⅎ x ψ
2 bj-vtoclg1f.maj ⊢ x = A → φ → ψ
3 bj-vtoclg1f.min ⊢ φ
4 elisset ⊢ A ∈ V → ∃ x x = A
5 1 2 3 bj-exlimmpi ⊢ ∃ x x = A → ψ
6 4 5 syl ⊢ A ∈ V → ψ