Metamath Proof Explorer


Theorem bj-vtoclg1f

Description: Reprove vtoclg1f from bj-vtoclg1f1 . This removes dependency on ax-ext , df-cleq and df-v . Use bj-vtoclg1fv instead when sufficient (in particular when V is substituted for _V ). (Contributed by BJ, 14-Sep-2019) (Proof modification is discouraged.)

Ref Expression
Hypotheses bj-vtoclg1f.nf 𝑥 𝜓
bj-vtoclg1f.maj ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
bj-vtoclg1f.min 𝜑
Assertion bj-vtoclg1f ( 𝐴𝑉𝜓 )

Proof

Step Hyp Ref Expression
1 bj-vtoclg1f.nf 𝑥 𝜓
2 bj-vtoclg1f.maj ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
3 bj-vtoclg1f.min 𝜑
4 bj-elisset ( 𝐴𝑉 → ∃ 𝑥 𝑥 = 𝐴 )
5 1 2 3 bj-exlimmpi ( ∃ 𝑥 𝑥 = 𝐴𝜓 )
6 4 5 syl ( 𝐴𝑉𝜓 )