Metamath Proof Explorer


Theorem bj-xpima1snALT

Description: Alternate proof of bj-xpima1sn . (Contributed by BJ, 6-Apr-2019) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion bj-xpima1snALT ⊢ ¬ X ∈ A → A × B X = ∅

Proof

Step Hyp Ref Expression
1 disjsn ⊢ A ∩ X = ∅ ↔ ¬ X ∈ A
2 xpima1 ⊢ A ∩ X = ∅ → A × B X = ∅
3 1 2 sylbir ⊢ ¬ X ∈ A → A × B X = ∅