Metamath Proof Explorer


Theorem brcnvssrid

Description: Any set is a converse subset of itself. (Contributed by Peter Mazsa, 9-Jun-2021)

Ref Expression
Assertion brcnvssrid A V A S -1 A

Proof

Step Hyp Ref Expression
1 ssid A A
2 brcnvssr A V A S -1 A A A
3 1 2 mpbiri A V A S -1 A