Metamath Proof Explorer


Theorem brcnvssrid

Description: Any set is a converse subset of itself. (Contributed by Peter Mazsa, 9-Jun-2021)

Ref Expression
Assertion brcnvssrid ⊢ A ∈ V → A S -1 A

Proof

Step Hyp Ref Expression
1 ssid ⊢ A ⊆ A
2 brcnvssr ⊢ A ∈ V → A S -1 A ↔ A ⊆ A
3 1 2 mpbiri ⊢ A ∈ V → A S -1 A