Metamath Proof Explorer


Theorem brcnvssrid

Description: Any set is a converse subset of itself. (Contributed by Peter Mazsa, 9-Jun-2021)

Ref Expression
Assertion brcnvssrid AVAS-1A

Proof

Step Hyp Ref Expression
1 ssid AA
2 brcnvssr AVAS-1AAA
3 1 2 mpbiri AVAS-1A