Metamath Proof Explorer


Theorem breqan12d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996)

Ref Expression
Hypotheses breq1d.1 ⊢ φ → A = B
breqan12i.2 ⊢ ψ → C = D
Assertion breqan12d ⊢ φ ∧ ψ → A R C ↔ B R D

Proof

Step Hyp Ref Expression
1 breq1d.1 ⊢ φ → A = B
2 breqan12i.2 ⊢ ψ → C = D
3 breq12 ⊢ A = B ∧ C = D → A R C ↔ B R D
4 1 2 3 syl2an ⊢ φ ∧ ψ → A R C ↔ B R D