Metamath Proof Explorer


Theorem brgric

Description: The relation "is isomorphic to" for graphs. (Contributed by AV, 28-Apr-2025)

Ref Expression
Assertion brgric ⊢ R ≃ 𝑔𝑟 S ↔ R GraphIso S ≠ ∅

Proof

Step Hyp Ref Expression
1 df-gric ⊢ ≃ 𝑔𝑟 = GraphIso -1 V ∖ 1 𝑜
2 grimfn ⊢ GraphIso Fn V × V
3 1 2 brwitnlem ⊢ R ≃ 𝑔𝑟 S ↔ R GraphIso S ≠ ∅