Metamath Proof Explorer


Theorem brlmic

Description: The relation "is isomorphic to" for modules. (Contributed by Stefan O'Rear, 25-Jan-2015)

Ref Expression
Assertion brlmic ⊢ R ≃ 𝑚 S ↔ R LMIso S ≠ ∅

Proof

Step Hyp Ref Expression
1 df-lmic ⊢ ≃ 𝑚 = LMIso -1 V ∖ 1 𝑜
2 lmimfn ⊢ LMIso Fn LMod × LMod
3 1 2 brwitnlem ⊢ R ≃ 𝑚 S ↔ R LMIso S ≠ ∅