Metamath Proof Explorer


Theorem cbvabdavw

Description: Change bound variable in class abstractions. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypothesis cbvabdavw.1 ⊢ φ ∧ x = y → ψ ↔ χ
Assertion cbvabdavw ⊢ φ → x | ψ = y | χ

Proof

Step Hyp Ref Expression
1 cbvabdavw.1 ⊢ φ ∧ x = y → ψ ↔ χ
2 1 cbvsbdavw ⊢ φ → t x ψ ↔ t y χ
3 df-clab ⊢ t ∈ x | ψ ↔ t x ψ
4 df-clab ⊢ t ∈ y | χ ↔ t y χ
5 2 3 4 3bitr4g ⊢ φ → t ∈ x | ψ ↔ t ∈ y | χ
6 5 eqrdv ⊢ φ → x | ψ = y | χ