Metamath Proof Explorer


Theorem cdlemg4g

Description: TODO: FIX COMMENT. (Contributed by NM, 25-Apr-2013)

Ref Expression
Hypotheses cdlemg4.l ⊢ ≤ ˙ = ≤ K
cdlemg4.a ⊢ A = Atoms ⁡ K
cdlemg4.h ⊢ H = LHyp ⁡ K
cdlemg4.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemg4.r ⊢ R = trL ⁡ K ⁡ W
cdlemg4.j ⊢ ∨ ˙ = join ⁡ K
cdlemg4b.v ⊢ V = R ⁡ G
cdlemg4.m ⊢ ∧ ˙ = meet ⁡ K
Assertion cdlemg4g ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → F ⁡ G ⁡ Q = Q ∨ ˙ V ∧ ˙ P ∨ ˙ Q

Proof

Step Hyp Ref Expression
1 cdlemg4.l ⊢ ≤ ˙ = ≤ K
2 cdlemg4.a ⊢ A = Atoms ⁡ K
3 cdlemg4.h ⊢ H = LHyp ⁡ K
4 cdlemg4.t ⊢ T = LTrn ⁡ K ⁡ W
5 cdlemg4.r ⊢ R = trL ⁡ K ⁡ W
6 cdlemg4.j ⊢ ∨ ˙ = join ⁡ K
7 cdlemg4b.v ⊢ V = R ⁡ G
8 cdlemg4.m ⊢ ∧ ˙ = meet ⁡ K
9 1 2 3 4 5 6 7 8 cdlemg4f ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → F ⁡ G ⁡ Q = Q ∨ ˙ V ∧ ˙ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W
10 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → K ∈ HL
11 simp1r ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → W ∈ H
12 simp21 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → P ∈ A ∧ ¬ P ≤ ˙ W
13 simp22l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → Q ∈ A
14 eqid ⊢ P ∨ ˙ Q ∧ ˙ W = P ∨ ˙ Q ∧ ˙ W
15 1 6 8 2 3 14 cdleme0cp ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A → P ∨ ˙ P ∨ ˙ Q ∧ ˙ W = P ∨ ˙ Q
16 10 11 12 13 15 syl22anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → P ∨ ˙ P ∨ ˙ Q ∧ ˙ W = P ∨ ˙ Q
17 16 oveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → Q ∨ ˙ V ∧ ˙ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W = Q ∨ ˙ V ∧ ˙ P ∨ ˙ Q
18 9 17 eqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ∈ T ∧ G ∈ T ∧ ¬ Q ≤ ˙ P ∨ ˙ V ∧ F ⁡ G ⁡ P = P → F ⁡ G ⁡ Q = Q ∨ ˙ V ∧ ˙ P ∨ ˙ Q