Metamath Proof Explorer


Theorem cgrcomland

Description: Deduction form of cgrcoml . (Contributed by Scott Fenton, 14-Oct-2013)

Ref Expression
Hypotheses cgrcomlrand.1 ⊢ φ → N ∈ ℕ
cgrcomlrand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
cgrcomlrand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
cgrcomlrand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
cgrcomlrand.5 ⊢ φ → D ∈ 𝔼 ⁡ N
cgrcomlrand.6 ⊢ φ ∧ ψ → A B Cgr C D
Assertion cgrcomland ⊢ φ ∧ ψ → B A Cgr C D

Proof

Step Hyp Ref Expression
1 cgrcomlrand.1 ⊢ φ → N ∈ ℕ
2 cgrcomlrand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
3 cgrcomlrand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
4 cgrcomlrand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
5 cgrcomlrand.5 ⊢ φ → D ∈ 𝔼 ⁡ N
6 cgrcomlrand.6 ⊢ φ ∧ ψ → A B Cgr C D
7 cgrcoml ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N → A B Cgr C D ↔ B A Cgr C D
8 1 2 3 4 5 7 syl122anc ⊢ φ → A B Cgr C D ↔ B A Cgr C D
9 8 adantr ⊢ φ ∧ ψ → A B Cgr C D ↔ B A Cgr C D
10 6 9 mpbid ⊢ φ ∧ ψ → B A Cgr C D