Metamath Proof Explorer


Theorem clmsubcl

Description: Closure of ring subtraction for a subcomplex module. (Contributed by Mario Carneiro, 16-Oct-2015)

Ref Expression
Hypotheses clm0.f ⊢ F = Scalar ⁡ W
clmsub.k ⊢ K = Base F
Assertion clmsubcl ⊢ W ∈ CMod ∧ X ∈ K ∧ Y ∈ K → X − Y ∈ K

Proof

Step Hyp Ref Expression
1 clm0.f ⊢ F = Scalar ⁡ W
2 clmsub.k ⊢ K = Base F
3 1 2 clmsubrg ⊢ W ∈ CMod → K ∈ SubRing ⁡ ℂ fld
4 subrgsubg ⊢ K ∈ SubRing ⁡ ℂ fld → K ∈ SubGrp ⁡ ℂ fld
5 3 4 syl ⊢ W ∈ CMod → K ∈ SubGrp ⁡ ℂ fld
6 cnfldsub ⊢ − = - ℂ fld
7 6 subgsubcl ⊢ K ∈ SubGrp ⁡ ℂ fld ∧ X ∈ K ∧ Y ∈ K → X − Y ∈ K
8 5 7 syl3an1 ⊢ W ∈ CMod ∧ X ∈ K ∧ Y ∈ K → X − Y ∈ K