Metamath Proof Explorer


Theorem cncfcn1

Description: Relate complex function continuity to topological continuity. (Contributed by Paul Chapman, 28-Nov-2007) (Revised by Mario Carneiro, 7-Sep-2015)

Ref Expression
Hypothesis cncfcn1.1 ⊢ J = TopOpen ⁡ ℂ fld
Assertion cncfcn1 ⊢ ℂ ⟶cn ℂ = J Cn J

Proof

Step Hyp Ref Expression
1 cncfcn1.1 ⊢ J = TopOpen ⁡ ℂ fld
2 ssid ⊢ ℂ ⊆ ℂ
3 1 cnfldtopon ⊢ J ∈ TopOn ⁡ ℂ
4 3 toponrestid ⊢ J = J ↾ 𝑡 ℂ
5 1 4 4 cncfcn ⊢ ℂ ⊆ ℂ ∧ ℂ ⊆ ℂ → ℂ ⟶cn ℂ = J Cn J
6 2 2 5 mp2an ⊢ ℂ ⟶cn ℂ = J Cn J