Metamath Proof Explorer


Theorem cocan2g

Description: Cancellation law for composition. A version of cocan2 with weaker hypotheses. (Contributed by Eric Schmidt, 29-Sep-2026)

Ref Expression
Hypotheses cocan2g.1 ⊢ φ → Fun ⁡ F
cocan2g.2 ⊢ φ → Rel ⁡ H
cocan2g.3 ⊢ φ → dom ⁡ H ⊆ ran ⁡ F
cocan2g.4 ⊢ φ → Rel ⁡ K
cocan2g.5 ⊢ φ → dom ⁡ K ⊆ ran ⁡ F
Assertion cocan2g ⊢ φ → H ∘ F = K ∘ F ↔ H = K

Proof

Step Hyp Ref Expression
1 cocan2g.1 ⊢ φ → Fun ⁡ F
2 cocan2g.2 ⊢ φ → Rel ⁡ H
3 cocan2g.3 ⊢ φ → dom ⁡ H ⊆ ran ⁡ F
4 cocan2g.4 ⊢ φ → Rel ⁡ K
5 cocan2g.5 ⊢ φ → dom ⁡ K ⊆ ran ⁡ F
6 1 2 3 cocanss2 ⊢ φ → H ∘ F ⊆ K ∘ F ↔ H ⊆ K
7 1 4 5 cocanss2 ⊢ φ → K ∘ F ⊆ H ∘ F ↔ K ⊆ H
8 6 7 anbi12d ⊢ φ → H ∘ F ⊆ K ∘ F ∧ K ∘ F ⊆ H ∘ F ↔ H ⊆ K ∧ K ⊆ H
9 eqss ⊢ H ∘ F = K ∘ F ↔ H ∘ F ⊆ K ∘ F ∧ K ∘ F ⊆ H ∘ F
10 eqss ⊢ H = K ↔ H ⊆ K ∧ K ⊆ H
11 8 9 10 3bitr4g ⊢ φ → H ∘ F = K ∘ F ↔ H = K