Metamath Proof Explorer


Theorem coeq2d

Description: Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1d.1 φA=B
Assertion coeq2d φCA=CB

Proof

Step Hyp Ref Expression
1 coeq1d.1 φA=B
2 coeq2 A=BCA=CB
3 1 2 syl φCA=CB