Metamath Proof Explorer


Definition df-pss

Description: Define proper subclass (or strict subclass) relationship between two classes. Definition 5.9 of TakeutiZaring p. 17. For example, { 1 , 2 } C. { 1 , 2 , 3 } ( ex-pss ). Note that -. A C. A (proved in pssirr ). Contrast this relationship with the relationship A C_ B (as defined in df-ss ). Other possible definitions are given by dfpss2 and dfpss3 . (Contributed by NM, 7-Feb-1996)

Ref Expression
Assertion df-pss ⊢ A ⊂ B ↔ A ⊆ B ∧ A ≠ B

Detailed syntax breakdown

Step Hyp Ref Expression
0 cA class A
1 cB class B
2 0 1 wpss wff A ⊂ B
3 0 1 wss wff A ⊆ B
4 0 1 wne wff A ≠ B
5 3 4 wa wff A ⊆ B ∧ A ≠ B
6 2 5 wb wff A ⊂ B ↔ A ⊆ B ∧ A ≠ B