Metamath Proof Explorer


Theorem df3o3

Description: Ordinal 3, fully expanded. (Contributed by RP, 8-Jul-2021)

Ref Expression
Assertion df3o3 ⊢ 3 𝑜 = ∅ ∅ ∅ ∅

Proof

Step Hyp Ref Expression
1 df-3o ⊢ 3 𝑜 = suc ⁡ 2 𝑜
2 df2o2 ⊢ 2 𝑜 = ∅ ∅
3 2 sneqi ⊢ 2 𝑜 = ∅ ∅
4 2 3 uneq12i ⊢ 2 𝑜 ∪ 2 𝑜 = ∅ ∅ ∪ ∅ ∅
5 df-suc ⊢ suc ⁡ 2 𝑜 = 2 𝑜 ∪ 2 𝑜
6 df-tp ⊢ ∅ ∅ ∅ ∅ = ∅ ∅ ∪ ∅ ∅
7 4 5 6 3eqtr4i ⊢ suc ⁡ 2 𝑜 = ∅ ∅ ∅ ∅
8 1 7 eqtri ⊢ 3 𝑜 = ∅ ∅ ∅ ∅