Metamath Proof Explorer


Theorem diag1a

Description: The constant functor of X . (Contributed by Zhi Wang, 19-Oct-2025)

Ref Expression
Hypotheses diag1.l ⊢ L = C Δ func D
diag1.c ⊢ φ → C ∈ Cat
diag1.d ⊢ φ → D ∈ Cat
diag1.a ⊢ A = Base C
diag1.x ⊢ φ → X ∈ A
diag1.k ⊢ K = 1 st ⁡ L ⁡ X
diag1.b ⊢ B = Base D
diag1.j ⊢ J = Hom ⁡ D
diag1.i ⊢ 1 ˙ = Id ⁡ C
Assertion diag1a ⊢ φ → K = B × X y ∈ B , z ∈ B ⟼ y J z × 1 ˙ ⁡ X

Proof

Step Hyp Ref Expression
1 diag1.l ⊢ L = C Δ func D
2 diag1.c ⊢ φ → C ∈ Cat
3 diag1.d ⊢ φ → D ∈ Cat
4 diag1.a ⊢ A = Base C
5 diag1.x ⊢ φ → X ∈ A
6 diag1.k ⊢ K = 1 st ⁡ L ⁡ X
7 diag1.b ⊢ B = Base D
8 diag1.j ⊢ J = Hom ⁡ D
9 diag1.i ⊢ 1 ˙ = Id ⁡ C
10 1 2 3 4 5 6 7 8 9 diag1 ⊢ φ → K = y ∈ B ⟼ X y ∈ B , z ∈ B ⟼ f ∈ y J z ⟼ 1 ˙ ⁡ X
11 fconstmpt ⊢ B × X = y ∈ B ⟼ X
12 fconstmpt ⊢ y J z × 1 ˙ ⁡ X = f ∈ y J z ⟼ 1 ˙ ⁡ X
13 12 a1i ⊢ y ∈ B ∧ z ∈ B → y J z × 1 ˙ ⁡ X = f ∈ y J z ⟼ 1 ˙ ⁡ X
14 13 mpoeq3ia ⊢ y ∈ B , z ∈ B ⟼ y J z × 1 ˙ ⁡ X = y ∈ B , z ∈ B ⟼ f ∈ y J z ⟼ 1 ˙ ⁡ X
15 11 14 opeq12i ⊢ B × X y ∈ B , z ∈ B ⟼ y J z × 1 ˙ ⁡ X = y ∈ B ⟼ X y ∈ B , z ∈ B ⟼ f ∈ y J z ⟼ 1 ˙ ⁡ X
16 10 15 eqtr4di ⊢ φ → K = B × X y ∈ B , z ∈ B ⟼ y J z × 1 ˙ ⁡ X