Metamath Proof Explorer


Theorem difxp1

Description: Difference law for Cartesian product. (Contributed by Scott Fenton, 18-Feb-2013) (Revised by Mario Carneiro, 26-Jun-2014)

Ref Expression
Assertion difxp1 ⊢ A ∖ B × C = A × C ∖ B × C

Proof

Step Hyp Ref Expression
1 difxp ⊢ A × C ∖ B × C = A ∖ B × C ∪ A × C ∖ C
2 difid ⊢ C ∖ C = ∅
3 2 xpeq2i ⊢ A × C ∖ C = A × ∅
4 xp0 ⊢ A × ∅ = ∅
5 3 4 eqtri ⊢ A × C ∖ C = ∅
6 5 uneq2i ⊢ A ∖ B × C ∪ A × C ∖ C = A ∖ B × C ∪ ∅
7 un0 ⊢ A ∖ B × C ∪ ∅ = A ∖ B × C
8 1 6 7 3eqtrri ⊢ A ∖ B × C = A × C ∖ B × C