Metamath Proof Explorer


Theorem disjeq

Description: Equality theorem for disjoints. (Contributed by Peter Mazsa, 22-Sep-2021)

Ref Expression
Assertion disjeq A=BDisjADisjB

Proof

Step Hyp Ref Expression
1 eqimss2 A=BBA
2 1 disjssd A=BDisjADisjB
3 eqimss A=BAB
4 3 disjssd A=BDisjBDisjA
5 2 4 impbid A=BDisjADisjB