Database
SUPPLEMENTARY MATERIAL (USERS' MATHBOXES)
Mathbox for Peter Mazsa
Disjoints vs. converse functions
disjeq
Next ⟩
disjeqi
Metamath Proof Explorer
Ascii
Unicode
Theorem
disjeq
Description:
Equality theorem for disjoints.
(Contributed by
Peter Mazsa
, 22-Sep-2021)
Ref
Expression
Assertion
disjeq
⊢
A
=
B
→
Disj
A
↔
Disj
B
Proof
Step
Hyp
Ref
Expression
1
eqimss2
⊢
A
=
B
→
B
⊆
A
2
1
disjssd
⊢
A
=
B
→
Disj
A
→
Disj
B
3
eqimss
⊢
A
=
B
→
A
⊆
B
4
3
disjssd
⊢
A
=
B
→
Disj
B
→
Disj
A
5
2
4
impbid
⊢
A
=
B
→
Disj
A
↔
Disj
B