Metamath Proof Explorer


Theorem disjeq

Description: Equality theorem for disjoints. (Contributed by Peter Mazsa, 22-Sep-2021)

Ref Expression
Assertion disjeq ⊢ A = B → Disj A ↔ Disj B

Proof

Step Hyp Ref Expression
1 eqimss2 ⊢ A = B → B ⊆ A
2 1 disjssd ⊢ A = B → Disj A → Disj B
3 eqimss ⊢ A = B → A ⊆ B
4 3 disjssd ⊢ A = B → Disj B → Disj A
5 2 4 impbid ⊢ A = B → Disj A ↔ Disj B