Metamath Proof Explorer


Theorem div2subd

Description: Swap subtrahend and minuend inside the numerator and denominator of a fraction. Deduction form of div2sub . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses div2subd.1 ⊢ φ → A ∈ ℂ
div2subd.2 ⊢ φ → B ∈ ℂ
div2subd.3 ⊢ φ → C ∈ ℂ
div2subd.4 ⊢ φ → D ∈ ℂ
div2subd.5 ⊢ φ → C ≠ D
Assertion div2subd ⊢ φ → A − B C − D = B − A D − C

Proof

Step Hyp Ref Expression
1 div2subd.1 ⊢ φ → A ∈ ℂ
2 div2subd.2 ⊢ φ → B ∈ ℂ
3 div2subd.3 ⊢ φ → C ∈ ℂ
4 div2subd.4 ⊢ φ → D ∈ ℂ
5 div2subd.5 ⊢ φ → C ≠ D
6 div2sub ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ ∧ C ≠ D → A − B C − D = B − A D − C
7 1 2 3 4 5 6 syl23anc ⊢ φ → A − B C − D = B − A D − C